A trumpet creates a sound intensity level of 1.34 102 dB at a distance of 0.90 m

Question

Explanation / Answer

Direct answers --> (a) 56.73 W/m^2 (b) 6.37E-4 W/m^2 Here's why down below.... Part A. I = P/A P= 0.800 W Calculate area directly in front of the trumpet d = 13.4 cm = 0.134 m r = 0.134 m / 2 r = 0.067 m A = pi * r^2 A = pi * (0.067 m)^2 A = pi * (0.004489 m^2) A = 0.0141 m^3 Put them together I = (0.800 W) / (0.0141 m^2) I = 56.73 W/m^2 Part B Distance = 10.0 m Since it's expanding in a perfect sphere, it'll be over a larger area, so we need the surface area of a sphere 4*pi*r^2 In this case, r = 10.0m A = 4 * pi * (100 m^2) A = 1,256.636 m^2 So I = P / A I = (0.800 W) / (1,256.6 m^2) I = 6.37E-4 W/m^2

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.