An electron with kinetic energy 1.50 keV circles in a plane perpendicular toa un

Question

An electron with kinetic energy 1.50 keV circles in a plane perpendicular toa uniform magnetic field. The orbit radius is 21.0 cm. The speed of the electron is2.29e^7 m/s The Magnitude Field is 6.22e^-4 T The Period seconds of Motionis 5.74e^-8 seconds. ElectronCharge=1.6e^-19 K=2.4e^-16
What is the frequency orcircling? In units Hz. The speed of the electron is2.29e^7 m/s The Magnitude Field is 6.22e^-4 T The Period seconds of Motionis 5.74e^-8 seconds. ElectronCharge=1.6e^-19 K=2.4e^-16
What is the frequency orcircling? In units Hz.

Explanation / Answer

In magnetic field ,force due to magnetic field =centripetal force                                                          Bv q = m v ^ 2 / R                                                       B q R = m v                                                                 = m R                                                           B q = m                                                                 = m ( 2 f ) from this frequency f = B q / ( 2m )                                 = ( 6.22 * 10 ^ -4 ) ( 1.6 * 10 ^ -19 ) / [ 2 * 3.14 * 9.1 * 10 ^-31 kg ]                                 = 0.174 * 10 ^ 8 Hz                                 = 17.4 * 10 ^ 6 Hz

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