A stone is thrown vertically upward with a speed of 11.5m/sfrom the edge of a cl

Question

A stone is thrown vertically upward with a speed of 11.5m/sfrom the edge of a cliff 78.0m high. The stone reaches the bottom of the cliff at 5.33s. Its speedjust before hitting is 40.734m/s. What total distance did ittravel? Answer needs to be in meters. A stone is thrown vertically upward with a speed of 11.5m/sfrom the edge of a cliff 78.0m high. The stone reaches the bottom of the cliff at 5.33s. Its speedjust before hitting is 40.734m/s. What total distance did ittravel? Answer needs to be in meters.

Explanation / Answer

Upward time = initial speed / g = 11.5/ 9.8 =    1.1735 seconds . upward average speed = initial speed / 2 = 5.75 m/s . upward distance = avg speed * time = 5.75 *1.1735   =   6.74745 meters . Downward time = 40.734 / 9.8 =  4.15653 seconds . downward avg speed = 40.734 / 2 =   20.367 m/s . downward distance = 20.367 * 4.15653 =    84.65606 meters . total distance = upward distance + downwarddistance = 6.74745 + 84.65606 =    91.40meters   (note: if you calculate the answer a differentway, you could get 91.50 meters due to a difference inrounding. )

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