A stone is dropped from rest from the top of a building. It takes t = 3.3 s for

Question

A stone is dropped from rest from the top of a building. It takes t = 3.3 s for it to reach the ground.

it to reach the ground. 17% Part (a) What is the initial velocity, vi, of the stone in m/s?
17% Part (b) What is the value of the magnitude of acceleration, in m/s2?
17% Part (c) Express the final velocity vf of a object travelling with an acceleration a for a time period t which starts with an initial velocity vi.
17% Part (d) Calculate the magnitude of vf in m/s.
17% Part (e) Express the displacement y of an object travelling with acceleration a during a time period t that has an initial velocity vi. 17% Part (f) Calculate the magnitude of y in meters. ©theexpertta.com

Explanation / Answer

(a) initial velocity=0 m/s

(b) accleration=g=9.8 m/s^2

(c) final velocity=g*t=9.8t

(d)vf=32.34 m/s

(e)y=(vi*t)+0.5*g*(t)^2

dispacement=(vf)^2/2g

(f)y=53.36 m

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