1. A small steel sphere falls with a terminal velocity in a viscousfluid of 2.00
ID: 1734855 • Letter: 1
Question
1. A small steel sphere falls with a terminal velocity in a viscousfluid of 2.00 cm/s. If the radius of the steel sphere is doubled,then what is the terminal velocity of the sphere?a. 1.00 cm/s
b. 2.00 cm/s
c. 4.00 cm/s
d. 6.0 cm/s
e. 8.00 cm/s
2. A viscous fluid is flowing through a small tube at a rate of2.00 × 104 m3/s. If the pressuredifference between one end of the tube and the other is doubled andthe radius is also doubled, then what is the rate of flow of thefluid?
a. 64 ×104m3/s
b. 56 ×104m3/s
c. 44 ×104m3/s
d. 37 ×104m3/s
e. 26 ×104m3/
Explanation / Answer
1. Answser : e We know that for the falling spherical steel ballVsg -Fv -FB = 0 Vsg- Vfg = 6rv (4/3)r3g[s-f] = 6 r vt Therefore we can observe that vt r2 ( terminal speed isdirectly proportional to square of the radius ) vt1/vt2 =(r1/r2)2 Given that vt1 =2.00cm/s r1 =r And vt2 =? r2 =2r Then vt2= (r2/r1)2vt1 = (2r/r)2(2.00cm/s) = (4)(2) = 8cm/s 2. We know that dV/dt = Av Use the above formula for the second one Vsg- Vfg = 6rv (4/3)r3g[s-f] = 6 r vt Therefore we can observe that vt r2 ( terminal speed isdirectly proportional to square of the radius ) vt1/vt2 =(r1/r2)2 Given that vt1 =2.00cm/s r1 =r And vt2 =? r2 =2r Then vt2= (r2/r1)2vt1 = (2r/r)2(2.00cm/s) = (4)(2) = 8cm/s 2. We know that dV/dt = Av Use the above formula for the second one = (2r/r)2(2.00cm/s) = (4)(2) = 8cm/s 2. We know that dV/dt = Av Use the above formula for the second one
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