1. A small steel sphere falls with a terminal velocity in a viscousfluid of 2.00

Question

1. A small steel sphere falls with a terminal velocity in a viscousfluid of 2.00 cm/s. If the radius of the steel sphere is doubled,then what is the terminal velocity of the sphere?

2. A viscous fluid is flowing through a small tube at a rate of2.00 × 104 m3/s. If the pressuredifference between one end of the tube and the other is doubled andthe radius is also doubled, then what is the rate of flow of thefluid?

3. A force of 100 N is applied to a rod with a diameter of 6.00 mm.The stress in the wire is:

4. A force of 20 N is applied to a wire with an un-stretched lengthof 2.5 m. The wire gets 2.00 mm longer. The strain in the wire is:

Explanation / Answer

(3) given forceF= 100N diameter = 6.00mm = 6.00*10-3 m radius = diameter/2 = 3.00*10-3 m stress = F/A = F/r2 =100/28.24*10-6 = 3.54*106 N (d) F = 20N     l = 2.5m e = 2.00*10-3 strain in the wire = e/l = 2.00*10-3/2.5 =0.0008 (a) terminal velocity = vt = 2.00cm/s terminal velocity r2 if radius is doubled    vt = k (2r)2=k4r2        = 2.00*4 = 8.00cm/s        = 2.00*4 = 8.00cm/s

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.