1. A gas undergoes a process in which pV = constant. The gas is initially at p 1
ID: 1715060 • Letter: 1
Question
1. A gas undergoes a process in which pV = constant. The gas is initially at p1 = 200 kPa and V1 = 2 m3. The final volume is V2 = 0.5 m3. Determine the final pressure, in kPa, and the work, in kJ, for the system.
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A box is traveling along a conveyor system similar to the one shown in the figure below. At the initial position shown, the box, which has a mass of 25 lbm, has a velocity of 2 ft/s. The vertical distance between the two horizontal belts is 5 ft and the ramp is frictionless.
a) calculate the initial kinetic energy of the box
b) calculate the velocity of the box when it reaches the bottom of the ramp
Explanation / Answer
1. We know that P1V1=P2V2
P is inversely proportional to volume
Final Pressure = 800KPa
Work done = P1V1 ln(V2/V1)
= 200*2*ln(0.5/2)
= -240kJ
2. (a) Kinetic Energy = 1/2MV2 Please provide the figure to solve the problem 2
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