1. A force of F = 65 N is used to drag a crate d = 7 m across a floor. The force
ID: 2127570 • Letter: 1
Question
1. A force of F = 65 N is used to drag a crate d = 7 m across a floor. The force is directed at an angle upward from the crate so that the vertical component of the force is Fv = 39 N and the horizontal component is Fh = 52 N as shown in the diagram.
4. A horizontally directed force of 32 N is used to pull a box a distance of 3.3 m across a tabletop. How much work is done by the 32 N-force?
_____________J
5. A net force of 40 N accelerates a 7-kg mass over a distance of 8 m.
A force of F = 65 N is used to drag a crate d = 7 m across a floor. The force is directed at an angle upward from the crate so that the vertical component of the force is Fv = 39 N and the horizontal component is Fh = 52 N as shown in the diagram. At the low point in its swing, a pendulum bob with a mass of 0.8 kg has a velocity of 11 m/s. A woman does 370 J of work to move a table 7 m across the floor. What is the magnitude of the force that the woman applied to the table if this force is applied in the horizontal direction? A horizontally directed force of 32 N is used to pull a box a distance of 3.3 m across a tabletop. How much work is done by the 32 N-force?Explanation / Answer
1. (a) W = F * d = 52 * 7 = 367 J
(b) As displacement in vertical direction is zero, hence work done is 0J.
(c) Total work done = 367 J.
2. (a) K.E. = 1/2 mv^2 = 0.4 * 121 =48.4 J
(b) at the highest point all kinetic energy will convert to potential energy
mgh = 48.4
h = 48.4 / 7.84 = 6.17 m
3. W = F * d
370 = F * 7
F = 52.85 N
4. W = F * d =32 * 3.3 = 105.6 J
5. (a) W = 40 * 8 = 320 J
(b) Net kinetic energy will be equal to total work done = 320J
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