1. A force of 83 Newtons is applied to a wirewith a diameter of 0.5 mm. What is

Question

1. A force of 83 Newtons is applied to a wirewith a diameter of 0.5 mm. What is the tensile stress (in SI units)in the wire?
2.A wire is 2.5 m long. After applying a forceto one end of the wire, it is now 2.506 m long. Calculate thetensile strain in the wire.
3.The use of the micrometer caliper is describedin Lab AA. According to Lab AA, the smallest marked division on themicrometer caliper is mm. 1. A force of 83 Newtons is applied to a wirewith a diameter of 0.5 mm. What is the tensile stress (in SI units)in the wire?
2.A wire is 2.5 m long. After applying a forceto one end of the wire, it is now 2.506 m long. Calculate thetensile strain in the wire.
3.The use of the micrometer caliper is describedin Lab AA. According to Lab AA, the smallest marked division on themicrometer caliper is mm.

Explanation / Answer

Stress is given as

      = F /A

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