1. A force of 22.04 N is applied tangentially to a wheel of radius 0.340 m and g

Question

1. A force of 22.04 N is applied tangentially to a wheel of radius 0.340 m and gives rise to an angular acceleration of 1.20 rad/s2. Calculate the rotational inertia of the wheel

A.) 7.8

B.) 4.68

C.) 55.36

D.) 6.24

E.) 9.36

F.) 3.86

2.) A string is wrapped around a pulley of mass M= 6.2-kg and a radius R and tied to a mass m = 12.8-kg. The mass m is released from rest, and it drops a distance h= 2.0m to the floor. Determine the speed of the mass m when it hits the floor

Need answer and units

3.) A string is wrapped around a pulley of mass M= 6.8-kg and a radius R and tied to a mass m = 14.4-kg. The mass m is released from rest, and it drops a distance h= 1.4m to the floor. Determine the aceleration of the system

Need answer and units

Explanation / Answer

torque=I*w

where I=inertia

w=angular speed=1.2 rad/sec

so 22.04*0.34=I*1.2

I=6.24

option D is correct.

2)let speed be v.

then angular speed of pulley=v/R

then total potential energy=kinetic energy of pulley +kinetic energy of mass

so 12.8*9.8*2=0.5*(6.2*R^2)*(v/R)^2+0.5*12.8*v^2

so v=5.14 m/s

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