A car is traveling at 56.8 mi/h on a horizontal highway. The accel of gravity is

Question

A car is traveling at 56.8 mi/h on a horizontal highway. The accel of gravity is 9.8 m/s^2. If the coef of friction between road and tires on a rainy day is 0.13, ~what is the minimum distance in which the car will stop? (1mi = 1.609). answer in units of m. ~what is the stopping distance when the surface is dry and the meu dry = 0.571? answer in units of m. A car is traveling at 56.8 mi/h on a horizontal highway. The accel of gravity is 9.8 m/s^2. If the coef of friction between road and tires on a rainy day is 0.13, ~what is the minimum distance in which the car will stop? (1mi = 1.609). answer in units of m. ~what is the stopping distance when the surface is dry and the meu dry = 0.571? answer in units of m.

Explanation / Answer

On a rainy day, Friction force =0.13*m*9.8 =1.274m Retardation = 1.274 m/s^2 = -a Now using v^2 - u^2 = 2as now putting the values u can get s(the min distance) easily. For 2nd part change the value of meu in Friction force equation. don't forget to change the value in m. Reply if any doubt.

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