1) A diver in midair has an angular velocity of 6.0 rad/s anda moment of inertia
ID: 1681627 • Letter: 1
Question
1) A diver in midair has an angular velocity of 6.0 rad/s anda moment of inertia of 1.6 kg·m2. He then pullsis arms and legs into a tuck position and his angular velocityincreases to 12 rad/s. The net external torque acting on the diveris zero. What is his moment of inertia in the tuck position? please i want the answer. 1) A diver in midair has an angular velocity of 6.0 rad/s anda moment of inertia of 1.6 kg·m2. He then pullsis arms and legs into a tuck position and his angular velocityincreases to 12 rad/s. The net external torque acting on the diveris zero. What is his moment of inertia in the tuck position? please i want the answer.Explanation / Answer
As the net external torque is 0, angular momentum isconserved, that means angular momentum is same in both thepositions. Angular momentum (L)= moment of inertia (I) x angular velocity() I11=I22 1.6 x 6 = 12 x I2 Therefore moment of inertia (I2)= 0.8Kg.m2 So moment of inertia in tuck position is 0.8Kg.m2 So moment of inertia in tuck position is 0.8Kg.m2Related Questions
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