1) A concave shaving mirror has a radius of curvature of +38.3 cm. It is positio
ID: 1286154 • Letter: 1
Question
1) A concave shaving mirror has a radius of curvature of +38.3 cm. It is positioned so that the (upright) image of a man's face is 2.58 times the size of the face. How far is the mirror from the face?
2) The figure gives the lateral magnification m of an object versus the object distance p from a spherical mirror as the object is moved along the mirror's central axis through a range of values for p. The horizontal scale is set by ps = 17.0 cm. What is the magnification of the object when the object is 22 cm from the mirror?
1) A concave shaving mirror has a radius of curvature of +38.3 cm. It is positioned so that the (upright) image of a man's face is 2.58 times the size of the face. How far is the mirror from the face? 2) The figure gives the lateral magnification m of an object versus the object distance p from a spherical mirror as the object is moved along the mirror's central axis through a range of values for p. The horizontal scale is set by ps = 17.0 cm. What is the magnification of the object when the object is 22 cm from the mirror?Explanation / Answer
1.
Because the radius of curvature is 38.3 cm, the focal length is f = r/2 = 19.15 cm.
An upright image 2.58 times the object size corresponds to a magni?cation of m = ?i/p = 2.58.
This implies that i = ?2.58p and
1/p + 1/i = 1/p ? 1/(2.58p) = 0.612/p
0.612/p = 1/f = 1/19.15
p = 0.612*19.15
p = 11.73
plz increase points for both answers
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