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1) A conducting bar of length moves to the right on two frictionless rails as sh

ID: 2009380 • Letter: 1

Question


1) A conducting bar of length moves to the right on two frictionless rails as shown in the figure below. A uniform magnetic field directed into the page has a magnitude of 0.290 T. Assume R = 8.90 and = 0.380 m.

 

 

(a)    At what constant speed should the bar move to produce an 8.70-mA current in the resistor?

 

(b)   At what rate is energy delivered to the resistor?

 

What is the electric field induced at a radius r = 1.00 cm from the axis of the solenoid? (Use the following as necessary: t. Let E be measured in millivolts/meter and t be measured in seconds.)

 

Explanation / Answer

(a)the emf produced by moving bar is

V = B*l*v

we also know that from Ohm's law

V = IR

so Blv = IR

v = IR/Bl

= 8.7*10-3 *8.9 /(0.290*0.380) = 0.703 m/s

(b) power delivered

P = I2 R = (8.7*10-3)2 * 8.9 = 6.736*10-4 W

or 0.6736 mW