1) A conducting bar of length moves to the right on two frictionless rails as sh
ID: 2009380 • Letter: 1
Question
1) A conducting bar of length moves to the right on two frictionless rails as shown in the figure below. A uniform magnetic field directed into the page has a magnitude of 0.290 T. Assume R = 8.90 and = 0.380 m.
(a) At what constant speed should the bar move to produce an 8.70-mA current in the resistor?
(b) At what rate is energy delivered to the resistor?
What is the electric field induced at a radius r = 1.00 cm from the axis of the solenoid? (Use the following as necessary: t. Let E be measured in millivolts/meter and t be measured in seconds.)
Explanation / Answer
(a)the emf produced by moving bar is
V = B*l*v
we also know that from Ohm's law
V = IR
so Blv = IR
v = IR/Bl
= 8.7*10-3 *8.9 /(0.290*0.380) = 0.703 m/s
(b) power delivered
P = I2 R = (8.7*10-3)2 * 8.9 = 6.736*10-4 W
or 0.6736 mW
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