1) A constant force of 100N acts on an object initially at rest through a parall

Question

1) A constant force of 100N acts on an object initially at rest through a parallel distance of 0.80m. (a) What is the final kinetic energy of the object. (b) If the object has a mass of 0.30 kg, what is its' final velocity?

2) (a) Calculate the centripetal force exerted on 2000 kg car that negotiates a 300m radius curve at 15.0 m/s. (b) Assuming an unbanked road find the minimum static frictioin between the tires and the road. (c) Coefficient of static friction.

3) A car has a mass of 2000kg and climbing a 20 degrees incline (to horizontal) at constant velocity of 15 m/s. How much work is done in one second?

Explanation / Answer

here,
Solution For 1:

as Work Done = F.D cosA
as force is parallel to displacement cos A = 0 degree
Therefore

W = F.D = 100 * 0.80
W = 80 J

As Work Done = Change in Kinetic energy
W = KEi + KEf
80 J = 0 + 0.5 * 0.30 *Vf^2
Vf = sqrt ( 80 / 0.5*0.30 )
Vf = 23.09 m/s
The Final Velocity will be 23.09 m/s

Now,
as KEf = 0.5 * m * Vf^2
KEf = 0.5 * 0.3 *23.09^2
KEf = 79.97 J

The Final Kinetic Energy will be Equal to 79.97 J

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