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A series circuit consists of a 0.048µF capacitor, a 0.110 µFcapacitor, and a 380

ID: 1665983 • Letter: A

Question

A series circuit consists of a 0.048µF capacitor, a 0.110 µFcapacitor, and a 380 V battery. Findthe charge for the following situations. (a) on each of the capacitors
1 µC (0.048 µF capacitor)
2 µC (0.110 µF capacitor)
(b) on each of the capacitors if they are reconnected in parallelacross the battery
3 µC (0.048 µF capacitor)
4 µC (0.110 µF capacitor) (a) on each of the capacitors
1 µC (0.048 µF capacitor)
2 µC (0.110 µF capacitor)
(b) on each of the capacitors if they are reconnected in parallelacross the battery
3 µC (0.048 µF capacitor)
4 µC (0.110 µF capacitor)

Explanation / Answer

(a) on each of the capacitors
1 µC (0.048 µF capacitor)=CV=12.54µC
2 µC (0.110 µF capacitor)=12.54µC
(b) on each of the capacitors if they are reconnected in parallelacross the battery
net capacity=0.158µF
total charge=60.04µC

3 µC (0.048 µF capacitor)=18.24µC
4 µC (0.110 µF capacitor) =41.8µC
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