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A series RLC circuit consists of a 43.0 resistor, a 4.00 mH inductor, and a 420

ID: 2262414 • Letter: A

Question

A series RLC circuit consists of a 43.0 resistor, a 4.00 mH inductor, and a 420 nF capacitor. It is connected to a 3.0 kHz oscillator with a peak voltage of 5.50 V.

A] What is the instantaneous emf (epsilon) when i = I ?

B] What is the instantaneous emf (epsilon) when i = 0 A and is decreasing?

C] What is the instantaneous emf (epsilon) when i = -I ?

From what I understand, the answer to C should be just the negated value of A, but I cannot figure out how to answer A. The units for all three values is V.

Explanation / Answer

A)when i=I A,

voltage across the resistor=43*I volts


now impedance of the circuit=2*pi*3000*0.004 - (1/(2*pi*420*10^(-9)*3000)=-50.9152 ohms

so voltage across the imedance=-50.9152 *I volts


so net voltage magnitude=sqrt(43*I ^2 + (-50.9152*I)^2)=66.64*I volts


b) 0 volt

c)magnitude=66.64*I volt

direction will be opposite.

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