Help with 8 and 9 please. At 8 the distance is 40 cm (0.09.2× 10-19)T (0,0,-9.2×
ID: 1649106 • Letter: H
Question
Help with 8 and 9 please.
At 8 the distance is 40 cm
(0.09.2× 10-19)T (0,0,-9.2× 10-19)T (1x10-7)/uexto) C,-(0,0, 1.8 × 10-20) T 0,0,-, 1.8 × 10-20)T .036)7 E. (0,0,5.1 10-19)T -F" (0,0,-5.1 × 10-19)T G. (0,0,3.3 x 1020) T (0,0,-3.3×10-20)T (-5.1 × 10-19, 7.7 × 10-190) T (5.1 × 10-19,-7.7 × 10-19,0) T « Answer: 8 12 pts) A thin coil has 60 circular turns of wire of radius 4 cm. The current in the wire is 8 amperes. At a distance of 40 cm from the center of the coil, along the axis of the coil, what is the approximate magnitude of the magnetic field contributed by the coil? n leo 1,8 r: o.oum A. 3.02×10-6 T - 7.54 × 10-6 T 3.77 × 10-6 T 75.4T B. Answer: 9.) [4 pts] Two plastic, hollow, ping-pong balls are rubbed with two different materials and acquire a uniform charge on their surfaces. The first acquires a charge of-9.0 × 10-9 C and is placed at location (0,0·06,0) m, while the second acquires a charge of 7.0 × 10-9 C and is placed at location (-0.03.-0.04,0) m. Both ping-pong balls are far from any other objects. What is the net electric field at the origin due to the ping-pong balls? A. (-1.51 × 104, 2.34 × 103, 0)V/m (-1 .5 1 × 1 04-427 x 1 01,0) V/m c) (1.51 × 104,427 × 104,0) Vin D. (1.51 × 104,-2.34 x 103, 0) V/m E. (7.00 × 104, 6.198 104, 0) V/m Answer:Explanation / Answer
Given
current I = 8 a, radius of the loop is r = 0.04 m, distance x is = 0.4 m
no of loops is n = 60
we know that the magnetic field at point x on the axis of the coil is
B = (n*muenot*I*r^2)/2(x^2+r^2)^(3/2)
substituting the values
B = 60*4pi*10^-7*8*0.04^2/(2(0.4^2+0.04^2)^(3/2)) T
B = 7.42812243*10^-6 T
answer is option C
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