Help with 5, 7, and 8 please. A dipole has charges +3 times 10^-5 C and -3 times

Question

Help with 5, 7, and 8 please.

A dipole has charges +3 times 10^-5 C and -3 times 10^-5 C. Along the bisector of this dipole, 0.8 m from its center, you measure an electric field of magnitude 1580 N/C. What is change separation between the two point charges? A. 5.98 times 10^-3 B. 2.99 times 10^-3 m C. 3.75 times 10^-3 m D. 5.46 times 10^-2 m E. 1.49 times 10^-3 m F. 5.15 m Answer: _____ Two locations in space, A and B, are in a region of uniform electric field E = (-400, 120, 0) V/m. Location A is at position (0.02, 0.03, 0) m and Location B is at position (-0050.060) m. What is the potential difference V_A - V_B? A. 31.6 V B. -316 V C. (-28, 3.6, 0) V D. (28, -3.6, 0) V E. -24.4 V At a particular instant, an electron is at the region, (0, 0, 0) m and is moving with a velocity of (0.75 times 10^4, m/s. What is the magnetic field at observation location (0.02, -0.03.0) m due to the moving electron at this instant A (0, 0, 9.2 times 10^-19) T B - (0, 0, -9.2 times 10^-19) T C. (0, 0, 1.8 times 10^-20) T D. (0, 0, -1.8 times 10^-20) T, E. (0, 0, -5.1 times 10^-19) T F. (0, 0, -5.1 times 10^-19) T G. (0, 0, 3.3 times 10^-20 T) H. (0, 0, -3.3 times 10^-20) T I. (-5.1 times 10^-19, 7.7 times 10^-19, 0) T J. (5.1 times 10^-19, -7.7 times 10^-19, 0) T A thin coil has 60 circular turns of wire of radius 4 cm. The current in the wire is 8 amperes. At a distance cm from the center of the coil, along the axis of the coil, what is the approximate magnitude of the contributed by the coil? A. 3.02 times 10^-6 T B. 37.7 times 10^-6 T C. 7.54 times 10^-6 T D. 37.7 T E. 75.4 T Two plastic, hollow, ping-pong balls are rubbed with two different materials and acquire a uniform their surfaces. The first acquires a charge of -9.0 times 10^-9 C and is placed at location (0, 0.06, 0) m, while acquires a charge of 7.0 times 10^-9 C and is placed at location (-0.03, -0.04, 0) m. Both ping-pong balls are other objects. What is the net electric field at the origin due to the ping-pong balls? A. (-1.51 times 10^4, 2.34 times 10^3, 0) V/m B. (-1.51 times 10^4, -4.27 times 10^4, 0)V/m C. (1.51 times 10^4, 4.27 times 10^4, 0) V/m D. (1.51 times 10^4, -2.34 times 10^3, 0)V/m E. (7.00 times 10^4, 6.19 times 10^4, 0)V/m

Explanation / Answer

5) ELECTRIC FIELD DUE TO DIPOLE ALONG THE BISECTING LINE

E = kqd/(a^2+d^2/4)^3/2

(a^2+d^2/4)^3/2/d = 9*10^9*3*10^-5/1580 = 170.9

(a^2+d^2/4)^3 = 29202.1d^2

here a = 0.8 m

by solving this equation wec an get d = 0.003 m = 3*10^-3

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