A hydraulic lift raises a 1000 kg automobile when a 500 N force is applied to th

Question

A hydraulic lift raises a 1000 kg automobile when a 500 N force is applied to the smaller piston. If the smaller piston has an area of 10 cm^2, what is the cross-section area (in cm^2)of the larger piston? 280 196 98 40 5 A person walks 500 m toward north, and then walks 1200 m toward east in a total of 10 minutes. What is the magnitude of the displacement relative to where the person starts? 500 m 700 m 1200 m 1300 m 1700 m In an arcade game a 0.1-kg disk is shot across a frictionless horizontal surface by compressing it against a spring and releasing it. The spring has a spring constant of 200 N/m and is compressed from its equilibrium position by 6.0 cm when the disk comes to a complete stop. As the disk gets released from the spring, what will be the speed (in m/s) of the disk when the spring is compressed by 2.0 cm? 1.3 2.3 2.5 4.9 5.4 If the frequency of a stationary train's whistle is 500 Hz, what is the frequency of the whistle heard by a person standing still on the platform as the train leaves at one tenth the speed of sound? The speed of sound is 343 m/s. 327 Hz 455 Hz 556 Hz 662 Hz 725 Hz A falling 0.1 kg has a speed of 3.0 m/s just before it hits the floor and an upward speed of 1.0 m/s immediately after it rebounds. The ball is in contact with the floor for 0.01 s. What is the magnitude (in N) of the average force exerted by the floor on the ball? 20 40 60 80 100 The Venturi tube shown in the figure below may be used as a fluid flowmeter: Suppose the device is used at a service station to measure the flow rate of gasoline (rho = 700 kg/m^3) through a hose having an inlet (left side) radius of 2.0 cm and an outlet (right side) radius of 1.0 cm. The difference in pressure is measured to be P_1 - P_2 = 565 Pa, what is the speed of the gasoline V_1 (in m/s) at the inlet? 0.33 0.45 0.52 0.67 0.73

Explanation / Answer

Answering Q.13 (As per rule, 1st que is answered)

We know that, Pressure=Force/area

Therefore, P1=P2

Hence, F1/A1 = F2/A2

Here, F1=1000*9.8(1000=Weight of the lift, 9.8=Gravity)

A1=?

F2= 500

A2=10

On substituting the values in the equations, we get

1000*9.8/A1 = 500/10

On solving,

A1=196cm2

Option B

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