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A hungry bear weighing 740 N walks out on a beam in an attempt to retrieve a bas

ID: 1789028 • Letter: A

Question

A hungry bear weighing 740 N walks out on a beam in an attempt to retrieve a basket of goodies hanging at the end of the beam (see the figure below). The beam is uniform, eighs 200 N, and is 7.00 m long, and t is supported by a wire ot an angle of -60.0.. The basket weighs 80.0 N. Goodies (a) Draw a force diagram for the beam. (Submit a fle with a maximum size of 1 MD.)Chose Fieno e selected This anewer has not been graded yet (b) When the bear is at x-1.18 m, find the tension in the wire supporting the beam on the lea end oft-bean.(Aesume the poem-+xdebeten i. to the eight ,d when the bear K-1 18m, find the com eresa, the force exerted bythe w the postive y direction is upward Include the sign of the value in your answ) (c) ir the wire can withstand a maximum tension of 750 N, what is the maximum distance the bear can walk before the wire breaks Need Help? L

Explanation / Answer

part b )

if x = 1.18 m then

sum of torque = (-740)(1.18) - (200)(3.5) -(80)(7) + Tsin60(7) = 0

T = 351.88 N

sum of all forces in x directon = 0

Rx = Tcos60 = 175.94 N

sum of all forces in y direction = 0

Ry = 1020 - Tsin60 = 715.26 N

part c )

if T = 750 N

sum of torque = (-740)x - (200)(3.5) - (80)(7) + (750 * sin60 * 7) = 0

x = 4.44 m

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