The moment of inertia of a uniform rod with the axis of rotation located at one

Question

The moment of inertia of a uniform rod with the axis of rotation located at one end of the rod is given by I = ML^2/3. What is the kinetic energy of a 140-cm rod with a mass of 250 g rotating at 1.60 rad/s? A) 2.76 J B) .21 J C) 1.96 J D) 0.70 J E) 2.35 J The drive belt for a pulley in a saw mill is applying a torque of 7.22 N-m to the pulley. Treat the pulley as a 150 cm diameter disk with a mass of 4.7 kg. What is the angular acceleration of the pulley? A) 1.22 rad/s^2 B) 4.10 rad/s^2 c) 10.5 rad/s^2 D) 20.8 rad/s^2

Explanation / Answer

9.

Moment of inertia of rod

I=(1/3)ML2=(1/3)*(250*10-3)*(140*10-2)2

I=0.1633 Kg-m2

Rotational kinetic energy

K=(1/2)IW2=(1/2)*0.1633*1.62

K=0.21 J

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.