The mole-fraction composition of a strand of a RNA molecule is [U] = 0.19 and [C

Question

The mole-fraction composition of a strand of a RNA molecule is [U] = 0.19 and [C] = 0.33. What can you say about the [A] and [G] of this RNA? [A] = 0.19, [G] = 0.33 [A] = 0.33, [G] = 0.19 [A] + [G] = 0.52 [A] + [G] = 0.48 There is not enough information to determine these concentrations. The antieancer drug cisplatin disrupts histone binding to DNA. supercoiling of DNA. chromatin-DNA binding. replication and transcription. None of the above In an enzymatic reaction in a test tube, the reaction will eventually reach equilibrium. Why does this not happen in living organisms?

Explanation / Answer

13. Given the mole fraction of a strand of RNA molecule, [U] = 0.19 and [C] = 0.33. We know for RNA the base pair is A-U and G-C. So the mole fraction for [A] and [G] would be,

A. [A] = 0.19 and [G] = 0.33

14. The anticancer drug cisplatin disrupts,

D. replication and transcription

15. In a general enzymatic reaction, the reaction initially increases with increase in substrate concentration, eventually reaches a maximum when all the active sites of enzyme are completely bound to the substrate molecule (saturation state for enzyme). This is however not true in living organism. In living organism any change in the substrate or the product concentration is controlled well, so that enzymes saturation state is never reached and thus enzymes always have their active sites free for further reaction.

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