A hollow, conducting sphere with an outer radius of 0.260 and an inner radius of

Question

A hollow, conducting sphere with an outer radius of 0.260 and an inner radius of 0.200 has a uniform surface charge density of +6.27 10 . A charge of -0.700 is now introduced into the cavity inside the sphere.

A)What is the new charge density on the outside of the sphere?

Express your answer with the appropriate units.

Part B

Calculate the strength of the electric field just outside the sphere.

Express your answer with the appropriate units.

I

Part C

What is the electric flux through a spherical surface just inside the inner surface of the sphere?

Express your answer with the appropriate units.

Explanation / Answer

1)

the new charge density on the outside of the sphere = p = 6.27 x 10^-6 - (7 x 10^-7 / 4pi*0.260^2)

p = 6.27 x 10^-6 - (8.24 x 10^-7)

p = 5.446 x 10^-6 C/m^2

2)

The strength of the electric field just outside the sphere is

E = 5.446 x 10^-6 / (8.85 x 10^-12)

E = 6.15 x 0^5 N/C

c)

The electric flux through a spherical surface just inside the inner surface of the sphere is

= -7 x 10^-7 / 8,85 x 10^-12

= 7.9096 x 10^4 Nm^2/C

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