Light enters a solid tube made of plastic having an index of refraction of 1.69

Question

Light enters a solid tube made of plastic having an index of refraction of 1.69 The light travels parallel to the upper part of the tube. (See (Figure 1)) You want to cut the face AD so that al the ight will reflect back Into the tube after it first strikes that face. What is the largest that theta can be if the tube is in air? Express your answer In degrees to three significant f If the tube is immersed n water of refractive index 1 33, whet is the largest that theta can be? Express your answer In degrees to three significant figures.

Explanation / Answer

According to the question provided we know that

PART A)

c = arcsin(1/1.69)=36.2788

so =90-=90-36.2788=53.721126 ========answer)

PART B)

c = arcsin(1.333/1.69)=52.06953

so =90-52.06953=37.93046 ===========ANSWER)

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