Light enters a solid tube made of plastic having an index of refraction of 1.69.

Question

Light enters a solid tube made of plastic having an index of refraction of 1.69. The light travels parallel to the upper part of the tube. You want to cut the face AB so that all the light will reflect back into the tube after it first strikes that face

PArt A

What is the largested angle that can be if the tube is in air

Angle max1=?percnet

Part B

If the tube is immersed in water of refractive index 1.333 what is the largest that angle can be?

Angle max2=?percent

%u03B8 can be if the tube is in the air

Part B i

PA

Light enters a solid tube made of plastic having an index of refraction of 1.69. The light travels parallel to the upper part of the tube. You want to cut the face AB so that all the light will reflect back into the tube after it first strikes that face What is the largested angle that can be if the tube is in air If the tube is immersed in water of refractive index 1.333 what is the largest that angle can be?

Explanation / Answer

Part A)max angle be i

then using snells law at cut surface for max i then sini/sin90= uair/uplastic gives i=36.278 degrees

part B) sini/sin90=uwater/uplastic gives i=51.9 degreres

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