1A) (For case A) What is the induced emf? 1B) (For case A) What is the induced c

ID: 1492102 • Letter: 1

Question

1A) (For case A) What is the induced emf?

1B) (For case A) What is the induced current?

1C) (For case A) What is the direction of the current?

2A) (For case B) What is the induced emf?

2B) (For case B) What is the induced current?

2C) (For case B) What is the direction of the current?

3A) (For case C) What is the induced emf?

3B) (For case C) What is the induced current?

3C) (For case C) What is the direction of the current?

Please show work.thanks

(a) B increasing at 0.50 T/s (b) B decreasing at 0.50 T/s (c) B decreasing at 0.50 T/s

induced emf = Nd(BA)/dt

emf = (dB/dt)*A = 0.5*(22/7)*(0.13/2)^2 = 0.00664 volt

current = 0.00664/0.5 = 0.01328 amp

and direction of current is counterclockwise. (from right hand tumb rule).

emf = (dB/dt)*A = 0.5*(22/7)*(0.13/2)^2 = 0.00664 volt

current = 0.00664/0.5 = 0.01328 amp

and direction of current is clockwise. (from right hand tumb rule).

emf = change in magnetic flux

and magnetic flux = B.A = BAcos(theta)

here theta = 90 so magnetic flux = 0

induced emf = 0

current = 0

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