You come across an open container which is filled with two liquids. Since the tw

Question

You come across an open container which is filled with two liquids. Since the two liquids have different density there is a distinct separation between them. Water fills the lower portion of the container to a depth of 0.218 m which has a density of 1.00 × 103 kg/m3. The fluid which is floating on top of the water is 0.342 m deep. If the absolute pressure on the bottom of the container is 1.049 × 105 Pa, what is the density of the unknown fluid? The acceleration due to gravity is g = 9.81 m/s2 and atmospheric pressure is P0 = 1.013 × 105 Pa.

Explanation / Answer

Here ,

Po = 1.013 *10^5 Pa

depth of water , dw = 0.218 m

density of water , pw = 1000 Kg/m^3

depth of unknown fluid , df = 0.342 m

at the bottom of the container , P = 1.049 *10^5 Pa

let the density of unknown fluid is p

at the bottom of container

P= Po +p * g * df + pw * g * dw

1.049 *10^5 = 1.013 *10^5 + 1000 * 9.8 * 0.218 + p * 9.8 * 0.342

solving for p

p = 436.7 Kg/m^3

the density of unkown fluid is 436.7 Kg/m^3

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