You charge an initially uncharged 86.1-mF capacitor through a 48.7-? resistor by

Question

You charge an initially uncharged 86.1-mF capacitor through a 48.7-? resistor by means of a 9.00-V battery having negligible internal resistance. Find the time constant of the circuit. What is the charge of the capacitor 1.55 time constants after the circuit is closed? What is the charge after a long time?

You charge an initially uncharged 86.1-mF capacitor through a 48.7-Q resistor by means of a 9.00-V battery having negligible internal resistance. Find the time constant of the circuit. What is the charge of the capacitor 1.55 time constants after the circuit is closed? What is the charge after a long time? Time constant: Number Charge: Number Charge after long time: Number

Explanation / Answer

Resistance , R = 48.7 Ohm

capacitance , C = 86.1 mF

T = R*C

T = 48.7 * 0.0861

T = 4.193 s

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t = 1.25 * T

Q = Qo * (1 - e^(-t/T))

Q = 86.1*10-3 * 9 * ( 1 - e^(-1.25))

Q = 0.5528 C

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Charge after a long time

Qo = 86.1*10-3*9

Qo = 0.7749 C

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