You come across an open container which is filled with two liquids. Since the tw

Question

You come across an open container which is filled with two liquids. Since the two liquids have different density there is a distinct separation between them. Water fills the lower portion of the container to a depth of 0.224 m which has a density of 1.00 * 10^3 kg/m^3. The fluid which is floating on top of the Water is 0.328 m deep. If the absolute pressure on the bottom of the container is 1.049 * 10^5 Pa, what is the density of the unknown fluid The acceleration due to gravity is g = 9.81 m/s^2 and atmospheric pressure is P_0= 1.013 * 10^5 Pa.

Explanation / Answer

Pressure due to water volume = (1,000 x 9.81 x 0.224) = 2197.44 Pa.
Add 101,300 Pa air pressure = 103497.44 Pa.
Pressure at bottom = 104,900 Pa.
Pressure due to unknown fluid = (104900 - 103497.44) = 1402.56 Pa.
(1402.56/0.328)/9.81 = 435.89 kg/m^3.

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