Tweedeldum and Tweedledee are carrying a uniform wooden board that is L = 3.00 m

Question

Tweedeldum and Tweedledee are carrying a uniform wooden board that is L = 3.00 m long and has a weight of w = 160 N . If Tweedledum applies an upward force of magnitude F1 = 60.0 N at the left end of the board, at what point and with what magnitude F2 of force does Tweedledee have to lift for the board to be carried?

Tweedledum applies a force of F1 at one end of the board. At what point d and with what force F2 does Tweedledee have to lift for the board to be carried?

Enter the values for F2 and d, separated by a comma, in newtons and meters respectively.

Explanation / Answer

length of the board L=3m

weight W=160 N

force due to Tweedledum is F1=60 N (at the left end)

force due to Tweedledee is F2 at d

by balancing the forces,

F1+F2=W

60+F2=160

===> F2=160-60=100

F2=100 N

torque due to F2 and W is,

W*(L/2)=F2*d

160*(3/2)=100*d

===> d=2.4 m (from the left end)

F2=100 N at d=2.4 m ----is answer

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