Twee puntladings, 10 nC en -5,0nC, word op die hoeke van 1.2 Two point charges,

Question

Twee puntladings, 10 nC en -5,0nC, word op die hoeke van 1.2 Two point charges, 10nC en-5,0nC, are placed at the reghoek geplaas, soos in die skets aangetoon. Bereken diecomers of a rectangle, as shown in the sketch. Calculate the potte en rigting van (a) die elektriese veld en (b) die elektriese magnitude and direction of (e) the electric feld and (D) the electric tensiaal in die middel tussen hierdie twee ladings. (10) potential in the middle between these point two charges(0) 4.0 cm 2.0 cm -5.0 nC

Explanation / Answer

given point charges

q1 = 10 nC

q2 = -5 nC

2d = sqroot(4^2 + 2^2) = 4.472 cm

hence

electric field at the midpoint = k(q1 + q2)/d^2 = 8.98*10^9(10 + 5)*10^-9 / (4.472/200)^2 = 269416.380515 V/m

direction along the line joining the two charges directed towards the -ve charge

electric potential at the midpoint = k(q1 - q2)/d = 8.98*10^9*5*10^-9/(4.472/200) = 2008.0500 V

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