A particle with charge 1.60×10 19 C is placed on the x axis in a region where th

Question

A particle with charge 1.60×1019 C is placed on the x axis in a region where the electric potential due to other charges increases in the +x direction but does not change in the y or z direction.

The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 1.60×1018 J . In what direction and through what potential difference VbVa does the particle move?

The particle moves to the left through a potential difference of VbVa= 10.0 V . The particle moves to the left through a potential difference of VbVa= -10.0 V The particle moves to the right through a potential difference of VbVa= 10.0 V . The particle moves to the right through a potential difference of VbVa= -10.0 V . The particle moves to the left through a potential difference of VbVa= 100 V . The particle moves to the right through a potential difference of VbVa= -100 V .

Explanation / Answer

change in electric potential energy = -(change in kinetic energy )

q (Vb- Va )= - del(k)

q(Va-Vb) = del(k)

Va-Vb = 10 V

Vb- Va = -10V

particle will move in the direction of decreasing electric field.so it will move towards left

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