A particle with charge 1.60*10^-19 C is placed on the x axis in a region where t

Question

A particle with charge 1.60*10^-19 C is placed on the x axis in a region where the electric potential due to other charges increases in the +x direction but does not change in the y or z direction. The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 6.40* 10^-19 J In what direction and through what potential difference V_b-V_a does the particle move? The particle moves to the left through a potential difference of V_b-V_a= 4.00 V. The particle moves to the left through a potential difference of V_b-V_a= - 4.00 V The particle moves to the right through a potential difference of V_b-V_a= 4.00 V The particle moves to the right through a potential difference of V_b-V_a= -4.00 V. The particle moves to the left through a potential difference of V_b-V_a= 40.0 V. The particle moves to the right through a potential difference of V_b-V_a= -40.0 V If the particle moves from point 0 to point c in the y direction, what is the change in its potential energy, U_c-U_b? +6.40*10^19J -6.40*10^19J 0

Explanation / Answer

The particle moves left through a potential difference Vb-Va= -4.00 V

in geneeral, if no forces other than the electric force act on a positively charged particle, the particle always moves toward a point at lower potential.

b) answer is zero, , every time a charged particle moves along a line of constant potential,its potential energy remains constant and the electric field does no work on the particle.

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