Scientists want to place a 3100 kg satellite in orbit around Mars. They plan to

Question

Scientists want to place a 3100 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem: 2 times the radius of Mars above the surface of the planet. Here is some informtion that will help solve this problem: mmars-6.4191 x 1023 kg mars -3.397 x 106 m G-6.67428 x 10-11 N-m2/kg? 1) What is the force of attraction between Mars and the satelite? N Submit 2) What speed should the satellite have to be in a perfectly circular orbit? m/s Submit

Explanation / Answer

(a)

F = G Mmars m/ R^2

here R = R mars + 2 R mars = 3 R mars

F = 6.67 * 10 ^-11 ( 6.4191 * 10 ^23 kg( 3100)/(3 ( 3.397 * 10^6 m)^2

=1277.79 N

(b)

v = sqrt G M mars/ R mars

= sqrt 6.67 * 10^-11 (( 6.4191 * 10 ^23 kg)/(3 ( 3.397 * 10^6 m)

=2.049 km/s

(c)

T = 2 pi R/ v

= 2 pi ((3 ( 3.397 * 10^6 m)/2049.7 m/s

=31223.8278 s ( h/ 3600 s) = 8.67 h

(d)

mass of planet and radius of orbit change the speed of the satelite.

As per guideleines I worked first four parts of the problem

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