A car is traveling with a constant speed along a road that makes a half of a squ

Question

A car is traveling with a constant speed along a road that makes a half of a square (two sides out of four). The average velocity of the car is SO miles/hour. What is its speed? A shooter aims horizontally at a target at the distance d at the same height us the shooter. The initial speed of the bullet is v. by what vertical distance h the bullet will miss the target? A car travels around a circle with a radius R. At what speed v_max the car begins to skid if the static friction coefficient is mu_s.

Explanation / Answer

Horizontal distance = d
Initial Speed of bullet, = v

So time taken to travel distance, t = Distance/Speed = d/v

Now,
Initial Vertical Speed = 0
Vertical acceleration = g = 9.8 m/s^2

So Height by which target will be missed,
s = u*t + 1/2*a*t^2
h = 0 + 1/2 g * (d/v)^2

h = 1/2*g * (d/v)^2 or 4.9 * (d/v)^2

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