A car is traveling around a horizontal circular track with radius r = 200 m at a

Question

A car is traveling around a horizontal circular track with radius r = 200 m at a constant speed v = 23 m/s as shown. The angle A = 18° above the x axis, and the angle B = 66° below the x axis.

What is the magnitude of the car’s acceleration?

What is the x component of the car’s acceleration when it is at point A

What is the y component of the car’s acceleration when it is at point A

What is the x component of the car’s acceleration when it is at point B

What is the y component of the car’s acceleration when it is at point B

As the car passes point B, the y component of its acceleration is

increasing

constant

decreasing

Explanation / Answer

a) There'll be only centripetal acceleration of magnitude v^2/r = 23^2/200 = 2.645 m/s^2
b) At point A, a_x = - a*cos(theta_A) = -2.645*cos(18 deg) = -2.516 m/s^2
c) At point A, a_y = -a*sin(theta_A) = -0.817 m/s^2
d) At point B, a_x = -a*cos(theta_B) = -1.076 m/s^2
e) At point B, a_y = -a*sin(theta_B) = 2.416 m/s^2
f) the y component is decreasing.

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