A car is traveling around a horizontal circular track with radius r = 210 m as s

Question

A car is traveling around a horizontal circular track with radius r = 210 m as shown. It takes the car t = 60 s to go around the track once. The angle A = 20° above the x axis, and the angle B = 65° below the x axis.

1) What is the magnitude of the car’s acceleration?

2) What is the x component of the car’s velocity when it is at point A

3What is the y component of the car’s velocity when it is at point A

4) What is the x component of the car’s acceleration when it is at point B

5) What is the y component of the car’s acceleration when it is at point B

6) As the car passes point B, the y component of its velocity is

increasing

constant

decreasing

Explanation / Answer

1) acc = v2 / r =

v = 2 pie r /t = 21.98m/s

so acc= 2.3 m/s2

2) vx = -vcos 70 degrees

3) vy = vsin 70 deg

4) ax = - 2.3 cos 65 deg

5) ay= 2.3 sin 65 deg

6) increasing

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