A) Two charges, +q and -q, are located in the x-y plane at points (0,+d/2) and (

Question

A) Two charges, +q and -q, are located in the x-y plane at points (0,+d/2) and (0,-d/2), respectively. Calculate the magnitude of the electric field at point P with the superposition principle.

. Data: q = 35.0 nC, d = 3.20 mm and P is at x = 64.0 mm.

B)In the previous problem, you can get an approximate answer for the electric field at point P by using the electric dipole approximation which is valid for the limit x>>d. Calculate the magnitude of the electric field at point P with this approximation and the same values for Q, d and x as in the previous problem.

Explanation / Answer

a) electric field due to charge q

= kq/r^2 = 9 x 10^9 x 35 x 10^-9 / (64^2 + (3.20/2)^2) x 10^-6

= 76856.26 N/C

magnityude of E due to -q will also be same but direction will be different.

angle made by x-axis = tan-1(3.20 / 2*64) = 1.432 degrees

Enet = 2Esin1.61 = 3841.61 N/C .....Ans

b) for dipole

E = kP / x^3

and p = qd   

E = kqd / x^3 for x >>> d

E = 9 x 10^9 x 35 x 10^-9 x 3.20 x 10^-3 / (64 x 10^-3)^3

E = 3845.21 N/C   

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