1. Two pure breeding plants with the genotypes ddPP and DDpp are crossed togethe
ID: 133121 • Letter: 1
Question
1. Two pure breeding plants with the genotypes ddPP and DDpp are crossed together to generate FI progeny with the genotype DdPp. F1 individuals were testcrossed to a homozygous parental strain (ddpp). The following data were obtained: Genotype DdPp Ddpp Ddpp ddPp observed #ofprogeny Expected# ofprogeny 190 210 310 290 Total: 1000 2 SO 2 SO A. In the table above, fill in the values for the expected number of progeny for each genotype based on the hypothesis that D and P are unlinked. B. What is the calculated y? value? .o C. How many degrees of freedom are there? i D. Are D and P linked or unlinked? (Use the z2 table attached below)Q E. as as 55 0.01 0.005 0.001 .004 s 8455 20 5246SIS 789 102 1 000000 000 207 0914 711 1004 357 .79 9.488 1113 127 140 146 115 78.762 72 73.761 87.213 91.242 043 14 33 119 78.935 018 76.955 90.700 4 83 907Explanation / Answer
Solution :
B)
Therefore, chi-square (X2) value as calculated above is = 41.60
C). Degrees of freedom(f) = number of categories - 1 = 4-1 = 3
D) Based on the table given and its observation D and P are linked.
Phenotype Observed (O) Expected (E) O-E (O-E)2 (O-E)2/E DdPp 190 250 -60 3600 14.40 ddpp 210 250 -40 1600 6.40 Ddpp 310 250 60 3600 14.40 ddPp 290 250 40 1600 6.40 1000 1000 41.60Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.