1. Two linked genes, (A) and (B), are separated by 18 m.u. A man with genotype A
ID: 220227 • Letter: 1
Question
1. Two linked genes, (A) and (B), are separated by 18 m.u. A man with genotype Aa Bb marries a woman who is aa bb. The man's father was AA BB. What is the probability that their first two children will both be ablab? A) 0.168 B) 0.0081 C) 0.032 D) 0.062 E) 0.13 2. A series of two-point crosses were carried out among twelve loci (a, b, c, d, e, f, g. h, i.j, k, I), producing the following recombination frequencies. Using these recombination frequencies, map the twelve loci, showing their linkage groups, the order of loci in each linkage group, and the distances between the loci of each 5015015015015014|14 | 50 | 50 | 50|50 5O | 50 | 8 | 8 | 50 | 50 | 50 | 11 | 16 | 50 50150150 | 50 | 50 | 50 | 50 | 50 | 50 50 50 50 50 14 5050 7 16 50 5050 38 50 50 50 509 50 50 10150150150150 50 50 5050 b 50 c 50 50 d 50 5050 e 50 85050 f50 850 50 16 g 450 50 5050 50 114 | 50 | 50 | 50 | 50 | 50 | 10 50|50|50|14 | 50 | 50 | 50 | 50 50 50 j5050 50 3 950 50 50 50 50||6 | 50 | 50 | 8 | 50 | 50 | 50 | 50 | 5 50 |5O | 50 | 50 | 7 | 50 | 50 | 50 | 50 | 7 | 50 | 50Explanation / Answer
1. The answer is
The map distance = % of recombinantion.
The total offspring (100%) = % of parental categories + % of the recombinant categories.
So, the % of parental categories = The total offspring (100%) - % of the recombinant categories.
For AB genes,
The map distance = % of recombinantion = 18%
% of parental categories = 100 - 18 = 82.
As each category contains two genotypes, the % of individual genotypes are
% of individual parental categories = 82/ 2 = 41% or 41/100
% of individual recombinant categories. 18/ 2 = 9% or 9/100.
So, the % of genotypes from this cross =
Parenal categories =
AB/ab = 41% or 41/100
ab/ab = 41% or 41/100
Recombinant categories =
Ab/ab = 9% or 9/100.
aB/ab = 9% or 9/100.
As the probability of one child with ab/ab is 41 % or 41/100 = 0.41,
the probability of two childern with ab/ab = 0.41*0.41 = 0.1681
so, the answer is A) 0.168
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