1. Two crates, one with a mass of m1 and the other with a mass of m2, are connec
ID: 1694686 • Letter: 1
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1. Two crates, one with a mass of m1 and the other with a mass of m2, are connected by a rope that passes over a pullley (frictionless). M1 is equal to 60 kg. So, if M1 accelerates downward at 4.5 m/s2, what is the value of mass m2? 2.A block on a frictionless horizontal surface is attached to spring with a force constant (k) of 600 N/m. The block is pulled a distance of x to the right of it's equilibrium and then released from rest. If the kinetic energy of the block at the instant it passes through its equilibrium position is 4.5 J, what was the initial displacement from the equilibrium position? 1. Two crates, one with a mass of m1 and the other with a mass of m2, are connected by a rope that passes over a pullley (frictionless). M1 is equal to 60 kg. So, if M1 accelerates downward at 4.5 m/s2, what is the value of mass m2? 2.A block on a frictionless horizontal surface is attached to spring with a force constant (k) of 600 N/m. The block is pulled a distance of x to the right of it's equilibrium and then released from rest. If the kinetic energy of the block at the instant it passes through its equilibrium position is 4.5 J, what was the initial displacement from the equilibrium position?Explanation / Answer
(1) m1 = 60 Kg Acceleration a = 4.5 m/s^2 m2 = ? Acceleration a = g(m1 - m2)/(m1 + m2) 4.5[60 + m2 ] = 9.8 [60 - m2] 270 + 4.5m2 = 588 - 9.8 m2 14.3 m2 = 318 m2 = 22.23 Kg (2) Force constant K = 600 N/m The initial displacement = x, (1/2)Kx^2 = 4.5 J 0.5 * 600 * x^2 = 4.5 x^2 = 0.015 So x = 0.122 mRelated Questions
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