1. Two large flat plates are separated by a distance d. The plates are connected

Question

1. Two large flat plates are separated by a distance d. The plates are connected to a battery a. The surface area of the face of each plate is AI. Write an expression for the capacitance in terms of A, and d b. A new capacitor is formed by attaching two uncharged metal plates, each with area A2, to the capacitor as shown. The battery remains connected. i. When the new plates are attached, does the electric potential difference between the plates increase, decrease, or remain the same? Explain. N N N Area A N Area A S Area A

Explanation / Answer

1. (a) C = e0 A1 / d

(b) (i) system is connected to battery so potential difference between plates will always be V0.

So remain the same.

(ii) Work done = q (deltaV )

= q0 V0

(iii) E = V0 / d

independent of A hence will remain constant.

(iv) E = sigma / e0

sigma = e0 V0 / d

it will remain constant.

(V) Q = sigma A = e0 V0 (A1 + A2) / d

greater than the original plate.

(vi) C' = e0 (A1 + A2) / d

increased

2. (a) sigma = Q1 / (A1 + A2)

(b) C = e0 (A1 + A2)/ d

V = Q / C = Q1 d / (e0 (A1 + A2))

(c) C = e0 (A1 + A2) / d

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