1. Two converging lenses with focal lengths of f 1 = 2.00 cm and f 2 = 5.00 cm a

Question

1.      Two converging lenses with focal lengths of f1 = 2.00 cm and f2 = 5.00 cm are situated 14.0 cm apart on a long optics bench. A 1.00 cm high object is placed 3.00 cm from the f1 lens and 17.0 cm from the f2 lens. Determine the following:

a)      The position of the final image (How many centimeters from the object and in what direction from the object? A carefully drawn diagram may help here.)

b)      The total magnification: mtotal

c)      Is the final image erect or inverted?

d)     Is the final image real or virtual?

e)      What is the height of the final image?

Please show all work and I would appreciate if you type instead of hand-write your work.

Explanation / Answer

Part A)

Start witht he first lens

1/f = 1/p + 1/q

1/2 = 1/3 + 1/q

q = 6 cm

For the second lens

1/5 = 1/8 + 1/q

q = 13.3 cm

Since the second image is 13.3 cm behind the second lens, that is...

13.3 + 14 + 3 = 30.3 cm away from the object

Part B)

M = -q/p times -q/p

M = -6/3 times -13.3/8

M = 3.33

Part C)

Since M is positive, the final image is erect

Part D)

Since q is positive, the final image is real

Part E)

M = h'/h

3.33 = h'/1

h' = 3.33 cm tall

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