A uniform electric field exists in the region between two oppositely charged par

Question

A uniform electric field exists in the region between two oppositely charged parallel plates 1.64 cm apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval 1.48×106 s .

Part A
Find the magnitude of the electric field.
Use 1.60×1019 C for the magnitude of the charge on an electron and 1.67×1027 kg for the mass of a proton.

Part B
Find the speed of the proton at the moment it strikes the negatively charged plate.

Explanation / Answer

Distance travelled = 1.64 * 10^-2 m
time taken = 1.48 * 10^-6 s
Initial Velcoity = 0 (As it is released from rest)

S = u*t + 0.5 *at^2
1.64 * 10^-2 = 0 + 0.5 * a * ( 1.48 * 10^-6 )^2
Solving for a
a = 1.5 * 10^10 m/s^2

Final Velocity = u + a*t
V = 0 + 1.5 * 10^10 * 1.48 * 10^-6 m/s
V = 2.2 * 10^4 m/s

We know , Force on proton in Electric Field, F =qE
We know, F = ma
ma = q*E
1.67*10^-27 * 1.5 * 10^10 = 1.6 * 10^-19 * E
Solving for E

E = 156.56 N/C

Part A)
Magnitud of Electric Field , E = 156.56 N/C

Part B)
Speed of proton when it strikes -ve Plate , V = 2.2 * 10^4 m/s

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