Given the circuit below. R1 is 69Ohms , R2 is 537Ohms , R3 is 115Ohms , E1 is 7.

Question

Given the circuit below. R1 is 69Ohms , R2 is 537Ohms , R3 is 115Ohms , E1 is 7.5V , E3 is 35V .

Part C

What is the current through the first resistorR1?

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Part D

What is the current through the second resistor R2?

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Part E

What is the current through the third resistorR3?

i1 = A Given the circuit below. R1 is 69Ohms , R2 is 537Ohms , R3 is 115Ohms , E1 is 7.5V , E3 is 35V . Part C What is the current through the first resistorR1? i1 = A SubmitMy AnswersGive Up Part D What is the current through the second resistor R2? i2 = A SubmitMy AnswersGive Up Part E What is the current through the third resistorR3? i3 = A SubmitMy AnswersGive Up

Explanation / Answer

Here , Let current in R1 is i1 to left

current in R2 is i2 right

current in the R3 is i3 left

Now , Using KCL

i1 -i2 + i3 = 0              ------(1)

Now , using KVL

7.5 - 69i1 - 537i2 = 0

69i1 + 537i2 = 7.5      -----(2)

again ,

35 - 115i3 - 537i2 = 0

537i2 + 115i3 = 35       -----(3)

solving 1 , 2 , 3

i1 = -0.13 A

i2 = 0.031 A

i3 = 0.161 A

the current in R1 is -0.13 A

current is R2 is 0.031 A

current in R3 is 0.161 A

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