Given the array declaration, int[]= new a int[20]; The firstelement is written a

Question

Given the array declaration, int[]= new a int[20]; The firstelement is written as: A)a[1]
B)a[0]
C)a
D)a[20]
E)a[19] Given the array declaration, int[] = new a int[20]; The last(legal) element is written as: A)a[2]
B)a[0]
C)a
D)a[20]
E)a[19]

Given the array declaration, int[]= new a int[20]; The firstelement is written as: A)a[1]
B)a[0]
C)a
D)a[20]
E)a[19] Given the array declaration, int[] = new a int[20]; The last(legal) element is written as: A)a[2]
B)a[0]
C)a
D)a[20]
E)a[19]

Given the array declaration, int[] = new a int[20]; The last(legal) element is written as: A)a[2]
B)a[0]
C)a
D)a[20]
E)a[19]
Given the array declaration, int[] = new a int[20]; The last(legal) element is written as:

Explanation / Answer

Question 1: The answer would be a[0]. The first element of an arrayis always the 0 index. Question 2: The last element would be a[19]. It will always be thelength of the array - 1 so in this case 20 - 1 = 19.

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