A wire carrying a current I = 2.7 mA comes in from far away, headed directly tow

Question

A wire carrying a current I = 2.7 mA comes in from far away, headed directly toward point C. At a distance R = 5.0 cm from point C, the wire makes a right-hand turn, at which point it starts following an arc of radius R centered on the point C. The wire curves through an arc that subtends an angle of pi/3 rad, and then makes another righthand turn after which it heads out to some distance point, directly away from point C. Find the magnetic field at the point C.

Hint #1: You should clearly be thinking of superposition from three parts of the current distribution. Hint #2: Biot-Savar

The qustion in the link below

http://capone.mtsu.edu/phys2120/HW_Problems/CH18-I-HWP.pdf

thanks

Explanation / Answer

we know for a comlete cilcr, B = mue*I/(2*R)

for an arc, B = (mue*I/2*R)*(theta/2*pi)

Here theta is the nagle made by the arc at the center.

B = (mue*I/2*R)*(pi/3)/(2*pi)

= mue*I/(12*R)

= 4*pi*10^-7*2.7*10^-3/(12*0.05)

= 5.65*10^-9 T or 5.65 nT

Here the direction of magnetic filed is peprpendiclrly out of the paper plane.

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