You come across an open container which is filled with two liquids. Since the tw

Question

You come across an open container which is filled with two liquids. Since the two liquids have different density there is a distinct separation between them. Water fills the lower portion of the container to a depth of 0.209 m which has a density of 1.00 103 kg/m3. The fluid which is floating on top of the water is 0.321 m deep. If the absolute pressure on the bottom of the container is 1.049 105 Pa, what is the density of the unknown fluid? The acceleration due to gravity is g = 9.81 m/s2 and atmospheric pressure is P0 = 1.013 105 Pa.

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Map sapling learning u come across an open container which is filled with two liquids. Since the two liquids have different aensity there is a distinct separation between them. Water fills the lower portion of the container to a depth of 0.209 m which has a density of 1.00 x 10 kg/m3. The fluid which is floating on top of the water is 0.321 m deep. If the absolute pressure on the bottom of the container is 1.049 × 105 Pa, what is the density of the unknown fluid? The acceleration due to gravity is g 9.81 m/s2 and atmospheric pressure is Po = 1.013 × 105 Pa. Number kg/m Previous Give Up & Vie w Solution Check Answer Next Exit- Hint The total absolute pressure at the bottom of the container is the sum of the contribution from atmospheric pressure, Po, the pressure due to the depth of water, Pw, and the pressure due to the depth of unknown liquid, P. The pressure at a certain depth in a liquid is dependent on the depth, h, the density of the liquid, p, and the acceleration due to gravity, g, i.e P= pgh

Explanation / Answer

0.209m.
0.321m.
1g/cc = 1,000kg/m^3.
Pressure due to water volume = (1,000 x 9.81 x 0.209) = 2050.29Pa.
Add 101,300Pa. air pressure = 103,320.86Pa.
Pressure at bottom = 104,900Pa.
Pressure due to unknown fluid = (104,900 - 103,320.86) = 1,579.14 Pa.
(1,579.14/0.321)/9.81 =465.17kg/m^3. density

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