You come across an open container which is filled with two liquids. Since the tw

Question

You come across an open container which is filled with two liquids. Since the two liquids have different density there is a distinct separation between them. Water fills the lower portion of the container to a depth of 0.230 m which has a density of 1.00 × 103 kg/m3. The fluid which is floating on top of the water is 0.300 m deep. If the absolute pressure on the bottom of the container is 1.049 × 105 Pa, what is the density of the unknown fluid? The acceleration due to gravity is g = 9.81 m/s2 and atmospheric pressure is P0 = 1.013 × 105 Pa.

Explanation / Answer

here,

depth of water , dw = 0.23 m

density of water , pw = 1 * 10^3 kg/m^3

pressure at the bottom of the container , Pb = 1.049 * 10^5 Pa

atmospheric pressure is P0 = 1.013 * 10^5 Pa

Pm = 1.049 * 10^5 - 1.013 * 10^5 = 3.6 * 10^3 Pa

The pressure of the water alone is
Pw = pw* g *dw = 2.254 kPa

so the pressure of the unknown liquid is( 3.6 KPa - 2.254 KPa) is 1.346 kPa

and its density is dl = Pw/ (g*du) = (1346/(9.81*0.30)) kg/m^3 = 457.82 kg/m^3

the density of the unknown liquid is 457.82 kg/m^3

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